What does MsgA(*) = MsgB(*) do?

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    • October 24, 2007 at 2:54 AM #18254
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        Some code I have picked up has 2 lines:

         

        SendMessage = DetailsMessage;

        SendMessage(*) = DetailsMessage(*);

         Inside a Construct Message.  What is the difference in meaning of these two assignments?

      • October 24, 2007 at 3:29 AM #18257
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          mchallis,

          The first line copies the message *content* – e.g. xml. The second line copies the message content *plus* the message *context*.

          Stephen W. Thomas has a quick overview here – http://geekswithblogs.net/sthomas/archive/2005/04/26/38286.aspx 

          Hope this helps,

          Nick. 

          • October 24, 2007 at 7:16 AM #18264
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              Nick,

              Actually, I seem to remember the first one copies both the message contents *and* the message context, while the second copies *only* the message context.

              • October 25, 2007 at 1:15 PM #18273
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                  Yep, I think Tomas is correct. 

                  The key is… when you do a transform inside an Orchestration the contaxt isn’t copied for you.  So the 2nd line (from above) would be needed to copy all the context data over if you need it inside the 2nd message.

                  This is not the same behavior as mapping on the Receive Port.

                  Stephen W. Thomas

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