Custom Soap Header

 I have checked out the link that you sent me. In all of the four options that you suggested, I am not sure how any of them would work for me.

You suggested this code.. msgOut.MsgPart1 = xmlDocMessage; in one of your responses.

But when I do that .(dot) nothing come up for me.

Any other way to send parameter values to Webmethod?

You don’t need the dot.  Your code would probably look like this:

msgOut = xmlDocMessage;

You only need a dot if you are sending a mulitpart message. The message you are sending to the service is a single XML file, so you don’t need a dot.

 So, If I understood correctly, I should have some schema for the Request.

In my case, I don’t have a seperate schema for the request. I get a whole Soapmessage as a XML document and I am doing Xpath queries(as discussed in our old posts) to retieve some values and then send them to the webmethod.

The schema that _tempuri produces is diffrent from what I get from the XMLDocument

No, you don’t need a schema for the request (if you were using the mapping method you would, but it sounds like you’re using the XmlDocument method).  

For example, assume your web service takes 2 parameters named param1 and param2.  You would create two string variables in orchestration view and call them strParam1 and strParam2.  Then you would assign to them using xpath().  Then you would build them into the XML string you are loading.  Your code would look something like this:

strParam1 = xpath(Request, “//*[local-name()=’param1′]”);

strParam2 = xpath(Request, “//*[local-name()=’param2′]”);

WebRequestXml = new System.Xml.XmlDocument();

WebRequestXml.LoadXml(“<WebMethodName xmlns=’http://www.tempuri.org’><param1>&#8221; + strParam1 + “</param1><param2>” + strParam2 + “</param2></WebMethodName>”);

To get the web request XML format right, you should generate an instance of the _tempuri schema.  Use the generated schema as a template for the XML string that you load in the LoadXml method.