What does MsgA(*) = MsgB(*) do?

Some code I have picked up has 2 lines:

 

SendMessage = DetailsMessage;

SendMessage(*) = DetailsMessage(*);

 Inside a Construct Message.  What is the difference in meaning of these two assignments?

mchallis,

The first line copies the message *content* - e.g. xml. The second line copies the message content *plus* the message *context*.

Stephen W. Thomas has a quick overview here - http://geekswithblogs.net/sthomas/archive/2005/04/26/38286.aspx 

Hope this helps,

Nick. 

Nick, Actually, I seem to remember the first one copies both the message contents *and* the message context, while the second copies *only* the message context.

Yep, I think Tomas is correct. 

The key is… when you do a transform inside an Orchestration the contaxt isn’t copied for you.  So the 2^nd line (from above) would be needed to copy all the context data over if you need it inside the 2^nd message.

This is not the same behavior as mapping on the Receive Port.

Stephen W. Thomas

Gents, I agree - my bad.

Please see:

So what does Msg2(*) = Msg1(*) do exactly?

Nick.